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Physics (Class 11)November 13, 2026
Physics (Class 11)2-4 Questions (8-16 Marks)15 Free Practice MCQs

Thermodynamics NEET Syllabus & 15-MCQ Online Test

Complete NTA NEET 2027 chapter syllabus breakdown, 5-year question weightage analysis, and 15 free NCERT line-by-line MCQs with official +4 / -1 marking.

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Dr. Nova, MBBS
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Thermodynamics 15-MCQ Test

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Question 1 of 15Work done in a cyclic thermodynamic process.

An ideal gas undergoes a cyclic process ABCA as shown in the given P−VP-V diagram. The net work done in the process is: (Diagram shows a triangle ABC with Pressure on y-axis and Volume on x-axis)

Academic Fact-Checked & NMC Verified

Reviewed by NEETnova Academic Council. Updated for NEET 2027 Syllabus.

Official NTA Data Verified

Comprehensive Master Guide: Thermodynamics for NEET UG


Section 1: Official NTA NEET Syllabus & Sub-Topic Checklist

Thermodynamics in Class 11 Physics bridges macroscopic thermal physics with microscopic mechanical energy. The National Testing Agency (NTA) and the National Medical Commission (NMC) mandate a rigorous conceptual and numerical understanding of this chapter for NEET UG.

Sub-Topic Checklist (NCERT Class 11 Physics, Chapter 12)

  • Thermal Equilibrium and Zeroth Law of Thermodynamics (NCERT Section 12.2)
  • Concept of Temperature and Internal Energy (NCERT Section 12.3)
  • First Law of Thermodynamics (NCERT Section 12.4)
  • Thermodynamic State Variables and Equation of State (NCERT Section 12.5)
  • Thermodynamic Processes:
  • Isothermal Process (NCERT Section 12.6.1)
  • Adiabatic Process (NCERT Section 12.6.2)
  • Isochoric Process (NCERT Section 12.6.3)
  • Isobaric Process (NCERT Section 12.6.4)
  • Cyclic Process
  • Heat Engines, Refrigerators, and Heat Pumps (NCERT Section 12.7)
  • Second Law of Thermodynamics: Kelvin-Planck and Clausius Statements (NCERT Section 12.8)
  • Reversible and Irreversible Processes (NCERT Section 12.9)
  • Carnot Engine and its Efficiency (NCERT Section 12.10)

Comparison Table: Deleted vs. Retained NTA NEET UG Syllabus

Retained in NTA NEET UG SyllabusDeleted / Out of Scope (per rationalized NCERT)
Zeroth, First, and Second Laws of ThermodynamicsKinetic Theory of Gases (Moved to separate chapter/deleted from combined unit in some rationalized texts, but Maxwell-Boltzmann distribution specifics are omitted)
Specific Heat Capacities (Cp,CvC_p, C_v) and Mayer's Relation (Cp−Cv=RC_p - C_v = R)Specific topics on intermolecular forces and detailed kinetic derivations
Isothermal, Adiabatic, Isobaric, Isochoric, and Cyclic PV graphsDetailed historical derivations of Carnot's theorem proofs beyond standard formula application
Work done in various thermodynamic processes (W=∫PdVW = \int P dV)Heat pump coefficients of performance detailed transient state analysis
Heat Engines, Carnot cycle efficiency, RefrigeratorsMolecular degrees of freedom detailed equipartition proofs (retained conceptually in thermal physics, omitted as heavy calculus derivations)

Section 2: Previous 5-Year NEET Question Distribution (2022-2026) & Marks Weightage

Thermodynamics is a high-yield unit. Questions frequently appear as direct formula substitutions, graphical interpretation of P-VP\text{-}V curves, or conceptual reasoning based on the First and Second Laws.

NEET Question Distribution (2022–2026)

Sub-TopicNEET 2022NEET 2023NEET 2024NEET 2025NEET 2026Total QuestionsEstimated Weightage (%)
First Law & Internal Energy (ΔU=Q−W\Delta U = Q - W)121127~28%
Thermodynamic Processes (P-VP\text{-}V Work, Isothermal, Adiabatic)212218~32%
Mayer's Relation & Specific Heats (Cp,CvC_p, C_v)101103~12%
Heat Engines, Refrigerators & Carnot Efficiency111126~24%
Zeroth Law & Thermal Equilibrium010001~4%
Total Questions per Year5555525100%

NEETnova Strategic Insight

  1. Assertion-Reasoning & Statement Questions: NTA frequently tests the sign conventions of the First Law (ΔU,Q,W\Delta U, Q, W) using Assertion-Reasoning formats. E.g., Assertion: Internal energy of an ideal gas depends only on its temperature. Reason: For an isothermal process involving an ideal gas, ΔU=0\Delta U = 0. Both statements must be evaluated independently for cause-and-effect validity.
  2. Graphical Analysis: Expect at least one question involving cyclic processes on a P-VP\text{-}V or V-TV\text{-}T diagram where net work done equals the enclosed area.
  3. Carnot Engine Efficiency Traps: Questions often test temperature scales. Aspirants frequently forget to convert Celsius temperatures (∘C^\circ\text{C}) to Kelvin (KK) when applying η=1−T2T1\eta = 1 - \frac{T_2}{T_1}.

Section 3: High-Yield NCERT Line-by-Line Core Concepts & Exceptions

1. Zeroth Law and Temperature

  • Statement: If systems AA and BB are each in thermal equilibrium with a third system CC, then AA and BB are in thermal equilibrium with each other.
  • Physical Significance: Defines Temperature as a property that dictates thermal equilibrium.

2. Internal Energy (ΔU\Delta U)

  • Internal energy of an ideal gas is strictly a function of temperature: ΔU=nCvΔT\Delta U = n C_v \Delta T
  • For an isothermal process of an ideal gas, since ΔT=0\Delta T = 0, ΔU=0\Delta U = 0.

3. First Law of Thermodynamics

  • Mathematical Form: ΔQ=ΔU+ΔW\Delta Q = \Delta U + \Delta W (Note: In chemistry NCERT, it is written as ΔU=q+w\Delta U = q + w due to work done on/by system sign conventions. In Physics NCERT, ΔQ=ΔU+PΔV\Delta Q = \Delta U + P\Delta V or ΔU=Q−W\Delta U = Q - W where WW is work done by the gas).
  • Sign Conventions (Physics NEET Standard):
  • ΔQ>0\Delta Q > 0: Heat added to the system.
  • ΔQ<0\Delta Q < 0: Heat removed from the system.
  • ΔW>0\Delta W > 0: Work done by the system (expansion, ΔV>0\Delta V > 0).
  • ΔW<0\Delta W < 0: Work done on the system (compression, ΔV<0\Delta V < 0).
  • ΔU>0\Delta U > 0: Temperature increases (ΔT>0\Delta T > 0).
  • ΔU<0\Delta U < 0: Temperature decreases (ΔT>0\Delta T > 0).

4. Thermodynamic Processes & Work Done (W=∫ViVfP dVW = \int_{V_i}^{V_f} P \, dV)

ProcessConstant QuantityEquation of StateWork Done (WW)Internal Energy Change (ΔU\Delta U)Heat Supplied (ΔQ\Delta Q)
IsothermalTemperature (T=constT = \text{const})PV=constPV = \text{const}nRT \ln≤\left(VfVi\frac{V_f}{V_i}\right) = 2.303 nRT \log_{10}≤\left(PiPf\frac{P_i}{P_f}\S\right)$00 (since $$\DeltaT=0 T = 0)Q=WQ = W
AdiabaticHeat (ΔQ=0\Delta Q = 0)PVγ=constPV^\gamma = \text{const}PiVi−PfVfγ−1\frac{P_i V_i - P_f V_f}{\gamma - 1} = $\frac{nR(T_i - T_f)}{\gamma - 1}$$−-\DeltaW W0$
IsobaricPressure (P=constP = \text{const})VT=const\frac{V}{T} = \text{const}P(Vf - Vi) = nR(Tf - Ti)$nC<sub>v</sub>n C<sub>v</sub> \DeltaT Tn C_p \Delta T$
IsochoricVolume (V=constV = \text{const})PT=const\frac{P}{T} = \text{const}0$nC<sub>v</sub>n C<sub>v</sub> \DeltaT Tn C_v \Delta T$

Where γ=CpCv=1+2f\gamma = \frac{C_p}{C_v} = 1 + \frac{2}{f} (ff = degrees of freedom).

5. Heat Engines and Carnot Efficiency

  • Efficiency (η\eta): beta=Work Done (W)Heat Absorbed (Q1)=Q1−Q2Q1=1−Q2Q1\\beta = \frac{\text{Work Done } (W)}{\text{Heat Absorbed } (Q_1)} = \frac{Q_1 - Q_2}{Q_1} = 1 - \frac{Q_2}{Q_1}
  • For a Carnot Engine operating between absolute temperatures T1T_1 (source) and T2T_2 (sink): Q2Q1=T2T1  ⟹  η=1−T2T1\frac{Q_2}{Q_1} = \frac{T_2}{T_1} \implies \eta = 1 - \frac{T_2}{T_1}
  • Coefficient of Performance (COP) of a Refrigerator: β=Q2W=Q2Q1−Q2=T2T1−T2\beta = \frac{Q_2}{W} = \frac{Q_2}{Q_1 - Q_2} = \frac{T_2}{T_1 - T_2}

6. Textual Exceptions & Boundary Conditions

  • Non-Ideal Gases: Real gases deviate from PV=nRTPV = nRT. Internal energy of a real gas depends on both temperature and volume ((∂U∂V)T≠0\left(\frac{\partial U}{\partial V}\right)_T \neq 0). However, unless specified otherwise, NEET physics assumes ideal gas behavior.
  • Cyclic Process: Over a complete thermodynamic cycle, the system returns to its initial state. Therefore, the net change in internal energy over a cycle is zero (∮ΔU=0\oint \Delta U = 0), implying ∮dQ=∮dW\oint dQ = \oint dW.

Section 4: Negative Marking Pitfalls & Calculation/Conceptual Traps

  1. Temperature Scale Trap in Carnot Engines:
  • Trap: Calculating efficiency using Celsius temperatures directly: η=1−27∘C127∘C=1−27127\eta = 1 - \frac{27^\circ\text{C}}{127^\circ\text{C}} = 1 - \frac{27}{127} (Incorrect!).
  • Correction: Always convert to Kelvin: T1=127+273=400 KT_1 = 127 + 273 = 400\text{ K}, T2=27+273=300 KT_2 = 27 + 273 = 300\text{ K}. Thus, η=1−300400=0.25\eta = 1 - \frac{300}{400} = 0.25 or 25%.
  1. Adiabatic vs. Isothermal Slope Confusion:
  • Trap: Assuming isothermal and adiabatic curves have the same steepness on a P-VP\text{-}V diagram.
  • Correction: The slope of an adiabatic curve (dPdV=−γPV\frac{dP}{dV} = -\gamma \frac{P}{V}) is γ\gamma times steeper than the slope of an isothermal curve (dPdV=−PV\frac{dP}{dV} = -\frac{P}{V}). Since γ>1\gamma > 1 for all gases, the adiabatic curve is always steeper than the isothermal curve at any given point.
  1. Work Done in Cyclic Processes (Clockwise vs. Anticlockwise):
  • Trap: Ignoring the direction of the cycle on a P-VP\text{-}V diagram.
  • Correction: A clockwise cycle on a P-VP\text{-}V diagram represents a heat engine where net work done is positive (W>0W > 0). An anticlockwise cycle represents a refrigerator/heat pump where net work done on the system is negative with respect to the gas expansion (W<0W < 0, net work extracted is negative).
  1. Sign Convention Discrepancies between Physics and Chemistry:
  • Trap: Applying the chemistry convention (ΔU=q+w\Delta U = q + w where w=−PΔVw = -P\Delta V for expansion) to NEET Physics numerical questions.
  • Correction: In NEET Physics, use ΔQ=ΔU+PΔV\Delta Q = \Delta U + P\Delta V. Expansion means positive work done by the gas, reducing available internal energy if heat is constant.
  1. Mayer's Relation Unit Mismatches:
  • Trap: Using Cp−Cv=RC_p - C_v = R with inconsistent units of calories and Joules.
  • Correction: R=8.314 J mol−1 K−1R = 8.314\text{ J mol}^{-1}\text{ K}^{-1}. If heat capacities are given in terms of calories, use R≈2 cal mol−1 K−1R \approx 2\text{ cal mol}^{-1}\text{ K}^{-1} (1 cal=4.184 J1\text{ cal} = 4.184\text{ J}).

Section 5: Step-by-Step 5-Day Mastery Strategy for NEET Aspirants

Day 1: Foundation, Zeroth Law, and First Law of Thermodynamics

  • Morning (2 Hours): Read NCERT Chapter 12 sections 12.1 to 12.4. Focus on the physical meaning of thermal equilibrium, internal energy as a state function, and sign conventions of the First Law.
  • Afternoon (1.5 Hours): Solve 30 target MCQs focusing strictly on ΔQ=ΔU+ΔW\Delta Q = \Delta U + \Delta W calculations.
  • Evening (30 Mins): Make flashcards for sign conventions of heat, work, and internal energy.

Day 2: Thermodynamic Processes and P-VP\text{-}V Work Calculations

  • Morning (2 Hours): Study NCERT Section 12.6. Derive and memorize work done formulas for Isothermal, Adiabatic, Isobaric, and Isochoric processes.
  • Afternoon (2 Hours): Practice finding work done from P-VP\text{-}V graphs (rectangular hyperbola vs. exponential curves). Solve 40 numerical questions.
  • Evening (30 Mins): Review adiabatic expansion/compression conditions (PVγ=constPV^\gamma = \text{const}, TVγ−1=constTV^{\gamma-1} = \text{const}, P1−γTγ=constP^{1-\gamma}T^\gamma = \text{const}).

Day 3: Specific Heats, Mayer’s Relation, and Cyclic Processes

  • Morning (1.5 Hours): Master degrees of freedom (ff), Cp=f+22RC_p = \frac{f+2}{2}R, Cv=f2RC_v = \frac{f}{2}R, and Mayer’s relation (Cp−Cv=RC_p - C_v = R).
  • Afternoon (2 Hours): Solve multi-step numerical problems involving cyclic processes (combinations of isochoric, isobaric, and isothermal legs).
  • Evening (30 Mins): Analyze previous years' NEET graph-based questions on cycles.

Day 4: Heat Engines, Refrigerators, and the Second Law

  • Morning (1.5 Hours): Read NCERT sections 12.7 to 12.10. Understand Kelvin-Planck and Clausius statements. Memorize efficiency and coefficient of performance formulas.
  • Afternoon (2 Hours): Solve numerical problems on Carnot engines (temperature conversion to Kelvin, maximum theoretical efficiency).
  • Evening (30 Mins): Revise Carnot theorem implications (efficiency is independent of working substance, depends only on temperatures of source and sink).

Day 5: Full-Chapter Mock Test, Error Analysis, and Revision

  • Morning (1 Hour): Timed 45-question grand test covering entire Thermodynamics (Physics).
  • Afternoon (2 Hours): Rigorous error analysis. Re-solve every incorrect question, paying special attention to calculation traps and sign convention errors.
  • Evening (1 Hour): Final skim of NCERT summary, highlighted text boxes, and formula sheet.

Chapter Sub-Topics for Revision

1Zeroth and First Law of Thermodynamics, Internal Energy
2Isothermal, Adiabatic, Isochoric and Isobaric Processes
3Second Law of Thermodynamics, Heat Engines and Reversible Processes
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Thermodynamics is a high-yield chapter in NEET Physics, consistently accounting for 2 to 4 questions in the exam, which translates to roughly 8 to 16 marks.

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