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Physics (Class 11)November 13, 2026
Physics (Class 11)2-4 Questions (8-16 Marks)15 Free Practice MCQs

System of Particles and Rotational Motion NEET Syllabus & 15-MCQ Online Test

Complete NTA NEET 2027 chapter syllabus breakdown, 5-year question weightage analysis, and 15 free NCERT line-by-line MCQs with official +4 / -1 marking.

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System of Particles and Rotational Motion 15-MCQ Test

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Question 1 of 15Rolling motion and acceleration on an inclined plane

A solid sphere of mass mm and radius RR is rolling down an inclined plane of inclination θ\theta without slipping. What is its linear acceleration?

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Reviewed by NEETnova Academic Council. Updated for NEET 2027 Syllabus.

Official NTA Data Verified

Comprehensive Master Guide: System of Particles and Rotational Motion for NEET UG

Section 1: Official NTA NEET Syllabus & Sub-Topic Checklist

To master "System of Particles and Rotational Motion" for NEET UG, you must align your preparation with the official National Testing Agency (NTA) syllabus, which strictly maps to Class 11 NCERT Physics (Part 1, Chapter 7).

Sub-Topic Checklist

  • Center of Mass (CM) of a Two-Particle System
  • Definition and mathematical formulation (XCM=m1x1+m2x2m1+m2X_{CM} = \frac{m_1 x_1 + m_2 x_2}{m_1 + m_2})
  • Generalization for a system of NN particles and continuous mass distributions
  • Motion of Center of Mass
  • Velocity, acceleration, and linear momentum of the center of mass
  • Conservation of linear momentum for a system of particles (F⃗ext=0  ⟹  P⃗=constant\vec{F}_{ext} = 0 \implies \vec{P} = \text{constant})
  • Vector Product of Two Vectors (Cross Product)
  • Geometric meaning, right-hand rule, and components calculation
  • Torque and Angular Velocity / Acceleration Relations
  • Definition of torque (τ⃗=r⃗×F⃗\vec{\tau} = \vec{r} \times \vec{F}), equilibrium of rigid bodies
  • Rotational analogue of Newton's second law (τ=Iα\tau = I\alpha)
  • Angular Momentum and Conservation Law
  • Definition of angular momentum (L⃗=r⃗×p⃗=Iω\vec{L} = \vec{r} \times \vec{p} = I\omega)
  • Law of conservation of angular momentum and its physical applications (e.g., ballet dancers, planetary motion)
  • Moment of Inertia (MI)
  • Definition, physical significance, dependence on axis of rotation and mass distribution
  • Radius of gyration (k=I/mk = \sqrt{I/m})
  • Theorems of Perpendicular and Parallel Axes
  • Statement, mathematical proof/derivation outline, and application to standard symmetric bodies (ring, disc, cylinder, sphere, rod)
  • Kinematics of Rotational Motion about a Fixed Axis
  • Equations of rotational kinematics (1 st, 2 nd, 3 rd rotational kinematic equations)
  • Dynamics of Rotational Motion
  • Comparison of translational and rotational motion variables and equations
  • Rolling Motion
  • Pure rolling, kinetic energy of rolling motion (translational + rotational), rolling down an inclined plane without slipping

NTA NEET UG Syllabus: Retained vs. Deleted Topics

StatusSub-Topic / ThemeNCERT ReferenceNEET UG Exam Relevance
RetainedCenter of Mass & Motion of CMSec. 7.2 & 7.3High (Direct numericals & conceptual matching)
RetainedTorque, Vector Product & EquilibriumSec. 7.4 & 7.5Critical (Equilibrium conditions: ∑F⃗=0,∑τ⃗=0\sum \vec{F} = 0, \sum \vec{\tau} = 0)
RetainedMoment of Inertia & TheoremsSec. 7.6, 7.7 & 7.8Max-Yield (Core calculation engine for rotational mechanics)
RetainedAngular Momentum & ConservationSec. 7.10 & 7.11High (Dynamic conceptual applications, e.g., moment of inertia changes)
RetainedRolling MotionSec. 7.14High (Acceleration down incline, velocity at base formulas)
DeletedNone (Entire chapter is active in updated NTA guidelines)Chapter 7 (Complete)Fully examinable

Section 2: Previous 5-Year NEET Question Distribution (2022-2026) & Marks Weightage

Rotational Motion is historically one of the highest-scoring and most feared chapters in NEET Physics. It regularly yields 2 to 3 questions per exam cycle (worth 8 to 12 marks).

Sub-Topic Distribution Table (NEET 2024–2026)

Sub-TopicNEET 2022NEET 2023NEET 2024NEET 2025NEET 2026Total QuestionsAverage Weightage (%)
Center of Mass & Collision/Motion01011320%
Torque & Rotational Equilibrium10101320%
Moment of Inertia & Radius of Gyration11110426.7%
Conservation of Angular Momentum01011320%
Rolling Motion & Kinetic Energy10100213.3%
Total Questions3333315100%

NEETnova Strategic Insight

  • Question Styles: Expect a blend of direct calculation-based formulas (especially Moment of Inertia matching or axis theorems) and conceptual conservation principles.
  • Statement & Matching Formats: Recent NTA patterns feature Match-the-Column questions linking geometrical bodies (Ring, Disc, Solid Sphere, Hollow Sphere) with their respective Radius of Gyration or Moment of Inertia about specific axes (e.g., tangent vs. diameter).
  • Time Trap: Rotational mechanics problems are designed to consume 3–4 minutes if you set up extended free-body diagrams needlessly. Mastery of symmetry, parallel/perpendicular axis theorems, and direct conservation laws is mandatory to solve problems within 75 seconds.

Section 3: High-Yield NCERT Line-by-Line Core Concepts & Exceptions

1. Center of Mass (CM) Core Equations

For a discrete system of particles along the X-axis: XCM=∑mixi∑mi=m1x1+m2x2+⋯+mnxnm1+m2+⋯+mnX_{CM} = \frac{\sum m_i x_i}{\sum m_i} = \frac{m_1 x_1 + m_2 x_2 + \dots + m_n x_n}{m_1 + m_2 + \dots + m_n} In vector form for 3D space: R⃗CM=1M∑i=1nmir⃗i\vec{R}_{CM} = \frac{1}{M} \sum_{i=1}^{n} m_i \vec{r}_i

  • Velocity of CM: V⃗CM=1M∑miv⃗i=P⃗totalM\vec{V}_{CM} = \frac{1}{M} \sum m_i \vec{v}_i = \frac{\vec{P}_{total}}{M}
  • Acceleration of CM: A⃗CM=∑F⃗extM\vec{A}_{CM} = \frac{\sum \vec{F}_{ext}}{M} Exception/Crucial Note: Internal forces (like internal explosions, spring forces, or molecular collisions within the system) do not affect the motion of the center of mass. F⃗int\vec{F}_{int} cancels out due to Newton's Third Law. If F⃗ext=0\vec{F}_{ext} = 0, then A⃗CM=0\vec{A}_{CM} = 0 and V⃗CM=constant\vec{V}_{CM} = \text{constant}.

2. Vector Product (Cross Product) Properties

C⃗=A⃗×B⃗=ABsin⁡θ n^\vec{C} = \vec{A} \times \vec{B} = AB \sin\theta \, \hat{n}

  • Non-commutative: A⃗×B⃗=−(B⃗×A⃗)\vec{A} \times \vec{B} = -(\vec{B} \times \vec{A})
  • Orthogonal unit vectors: i^×j^=k^,j^×k^=i^,k^×i^=j^\hat{i} \times \hat{j} = \hat{k}, \quad \hat{j} \times \hat{k} = \hat{i}, \quad \hat{k} \times \hat{i} = \hat{j} i^×i^=j^×j^=k^×k^=0\hat{i} \times \hat{i} = \hat{j} \times \hat{j} = \hat{k} \times \hat{k} = 0

3. Torque (τ⃗\vec{\tau}) and Angular Momentum (L⃗\vec{L})

  • Torque: τ⃗=r⃗×F⃗=rFsin⁡θ n^=(r⊥)F=r(F⊥)\vec{\tau} = \vec{r} \times \vec{F} = r F \sin\theta \, \hat{n} = (r_\perp) F = r (F_\perp) Equilibrium Condition: For static equilibrium, ∑F⃗ext=0\sum \vec{F}_{ext} = 0 and ∑τ⃗ext=0\sum \vec{\tau}_{ext} = 0 about any arbitrary point.
  • Angular Momentum: L⃗=r⃗×p⃗=m(r⃗×v⃗)\vec{L} = \vec{r} \times \vec{p} = m (\vec{r} \times \vec{v})
  • For a rigid body rotating about a fixed axis: L=IωL = I\omega
  • Newton’s Second Law in Rotational Form: τ⃗ext=dL⃗dt\vec{\tau}_{ext} = \frac{d\vec{L}}{dt}
  • Conservation Law: If τ⃗ext=0\vec{\tau}_{ext} = 0, then L⃗=constant  ⟹  I1ω1=I2ω2\vec{L} = \text{constant} \implies I_1\omega_1 = I_2\omega_2.

4. Comprehensive Moment of Inertia (MI) Matrix

BodyAxis of RotationMoment of Inertia (II)Radius of Gyration (k=I/Mk = \sqrt{I/M})
Thin Circular RingThrough center, perpendicular to planeMR2MR^2R$
Thin Circular RingDiameter12MR2\frac{1}{2}MR^2$\frac{R}{2\sqrt{2}}$$
Thin Circular RingTangent in plane32MR2\frac{3}{2}MR^2R$\sqrt{32\frac{3}{2}}$$
Thin Circular RingTangent perpendicular to plane2MR22MR^2R$\sqrt{2}$$
Circular DiscThrough center, perpendicular to plane12MR2\frac{1}{2}MR^2$\frac{R}{2\sqrt{2}}$$
Circular DiscDiameter14MR2\frac{1}{4}MR^2$\frac{R}{2}$$
Circular DiscTangent in plane54MR2\frac{5}{4}MR^2\frac{$$\sqrt{5}$$}{2}R$
Solid CylinderGeometric axis12MR2\frac{1}{2}MR^2$\frac{R}{2\sqrt{2}}$$
Hollow CylinderGeometric axisMR2MR^2R$
Thin RodCenter, perpendicular to length112ML2\frac{1}{12}ML^2$\frac{L}{12\sqrt{12}}$$
Thin RodEnd, perpendicular to length13ML2\frac{1}{3}ML^2$\frac{L}{3\sqrt{3}}$$
Solid SphereDiameter25MR2\frac{2}{5}MR^2R$\sqrt{25\frac{2}{5}}$$
Solid SphereTangent75MR2\frac{7}{5}MR^2R$\sqrt{75\frac{7}{5}}$$
Spherical Shell (Hollow)Diameter23MR2\frac{2}{3}MR^2R$\sqrt{23\frac{2}{3}}$$
Spherical Shell (Hollow)Tangent53MR2\frac{5}{3}MR^2R$\sqrt{53\frac{5}{3}}$$

5. Theorems of Axes

  • Perpendicular Axis Theorem (Valid only for planar/2D lamina): Iz=Ix+IyI_z = I_x + I_y where xx and yy are orthogonal axes lying in the plane of the lamina, and zz is perpendicular to the plane passing through their intersection.
  • Parallel Axis Theorem (Valid for any rigid body, 2D or 3D): I=ICM+Md2I = I_{CM} + M d^2 where ICMI_{CM} is the moment of inertia about an axis passing through the center of mass, II is the parallel axis, and dd is the perpendicular distance between the two parallel axes.

6. Rolling Motion Mechanics

A body in pure rolling executes both rotational motion about its center of mass and translational motion of its center of mass.

  • Condition for Pure Rolling (No Slipping): vCM=RωandaCM=Rαv_{CM} = R\omega \quad \text{and} \quad a_{CM} = R\alpha
  • Total Kinetic Energy of Rolling Body: K = K_{trans} + K_{rot} = \frac{1}{2}M v_{CM}^2 + \frac{1}{2}$I \omega^2$$$$ Substituting $I = k^2 M$ and $\omega = \frac{v}{R}$: K = \frac{1}{2} M v_{CM}^2 \left(1 + \frac{k^2}{R^2}$\right)$$$$
  • Acceleration Down an Inclined Plane of angle θ\theta: $$a = \frac{g \sin\theta}{1 + \frac{k^2}{R^2}$}$$$$
  • Velocity at the Base of Inclined Plane of height hh: $$v = \sqrt{\frac{2gh}{1 + \frac{k^2}{R^2}$}}$$$$

Section 4: Negative Marking Pitfalls & Calculation/Conceptual Traps

  1. Misidentifying the Axis of Rotation: Trap: Applying standard formulas without verifying if the axis passes through the center of mass or an endpoint/tangent. Correction: Always check whether the question specifies "about its center" or "about a natural edge/tangent." Memorize the shift values using the Parallel Axis Theorem (+Md2+Md^2).

  2. Confusing Perpendicular Axis Theorem Applicability: Trap: Trying to apply Iz=Ix+IyI_z = I_x + I_y to a 3D object like a solid sphere or cylinder. Correction: The Perpendicular Axis Theorem is exclusively valid for two-dimensional laminar (flat planar) objects. For 3D objects, use the Parallel Axis Theorem or direct integration/symmetry arguments.

  3. Rolling Without Slipping vs. Sliding Sign Conventions: Trap: Assuming friction acts upward along an incline during rolling. Correction: Static friction (fsf_s) acts upward along the incline to provide the necessary torque for rotation, but its magnitude is less than μsN\mu_s N. If the surface is smooth (f=0f=0), the body undergoes sliding mixed with rotation, and the pure rolling condition v=Rωv = R\omega fails instantly.

  4. Conservation of Angular Momentum Vector Direction: Trap: Assuming conservation applies when any force acts on the system. Correction: Angular momentum is conserved only if the net external torque (τ⃗ext\vec{\tau}_{ext}) is zero. Internal torques (such as a person walking on a rotating turntable) do not change the total angular momentum of the system.

  5. Radius of Gyration Confusion (kk): Trap: Mixing up the radius of gyration kk with the radius of the object RR. Correction: kk depends entirely on the axis of rotation and mass distribution. For a ring about its central axis, k=Rk = R, but for a disc about its central axis, k=R/2k = R/\sqrt{2}. Always substitute k2R2\frac{k^2}{R^2} ratios carefully in rolling kinetics.


Section 5: Step-by-Step 5-Day Mastery Strategy for NEET Aspirants

Day 1: Center of Mass, Motion of CM & Cross Product Basics

  • Morning (2 Hours): Read NCERT Chapter 7 Sections 7.1, 7.2, and 7.3 line-by-line. Focus on discrete two-particle coordinate calculations and center of mass of uniform symmetrical bodies (semi-circular ring/disc conceptual results).
  • Afternoon (1.5 Hours): Master vector cross products (i^,j^,k^\hat{i}, \hat{j}, \hat{k} expansion via determinants). Practice finding velocity and acceleration of the center of mass for two-body systems.
  • Evening (1 Hour): Solve 30 target MCQ practice problems specifically on CM coordinate shifts and internal explosion momentum conservation.

Day 2: Torque, Rotational Equilibrium & Angular Velocity Kinematics

  • Morning (2 Hours): Study Sections 7.4 and 7.5. Understand vector definition of torque (τ⃗=r⃗×F⃗\vec{\tau} = \vec{r} \times \vec{F}) and the conditions of static equilibrium (∑F⃗=0,∑τ⃗=0\sum \vec{F} = 0, \sum \vec{\tau} = 0).
  • Afternoon (1.5 Hours): Practice ladder problems, seesaw/beam balance problems, and hinge force calculations. Learn how to choose a smart pivot point where unknown torques become zero (r=0r=0).
  • Evening (1 Hour): Revise rotational kinematic equations (ω=ω0+αt\omega = \omega_0 + \alpha t, θ=ω0t+12\theta = \omega_0 t + \frac{1}{2}α t2,, ω^2 = \omega_02 + 2αθ$) and solve 25 high-yield MCQs.

Day 3: Moment of Inertia, Radius of Gyration & Axis Theorems

  • Morning (2 Hours): Study Sections 7.6, 7.7, and 7.8. Memorize the MI table for standard bodies (Ring, Disc, Rod, Solid/Hollow Spheres, Cylinders) across central axes.
  • Afternoon (2 Hours): Deep dive into the Parallel Axis Theorem and Perpendicular Axis Theorem. Practice deriving tangent-axis moments of inertia and diameter-axis moments of inertia.
  • Evening (1 Hour): Solve 35 assertion-reasoning and match-the-column questions focusing exclusively on moment of inertia and radius of gyration ratios.

Day 4: Angular Momentum & Conservation Law

  • Morning (1.5 Hours): Study Sections 7.10 and 7.11. Focus on the vector relation L⃗=r⃗×p⃗\vec{L} = \vec{r} \times \vec{p} and scalar relation L=IωL = I\omega.
  • Afternoon (2 Hours): Master rotational analogues (F→τF \to \tau, m→Im \to I, v→ωv \to \omega, p→Lp \to L). Solve classic conservation of angular momentum problems:
  • A child sitting on a rotating turntable who stands up or catches a mass.
  • A falling mass sticking to the edge of a rotating disc.
  • Evening (1 Hour): Solve 30 previous years' questions (PYQs) from NEET 2018–2024 related to angular momentum changes and frequency shifts.

Day 5: Rolling Motion, Comprehensive Revision & Full Chapter Mock Test

  • Morning (1.5 Hours): Study Section 7.14 on rolling motion without slipping. Understand kinetic energy partitioning (12Mv2:12Iω2\frac{1}{2}Mv^2 : \frac{1}{2}I\omega^2) and acceleration/velocity formulas down inclined planes.
  • Afternoon (1.5 Hours): Create a one-page formula flashcard summarizing all MI expressions, rolling acceleration formulas, and conservation laws.
  • Evening (1.5 Hours): Take a timed 45-question Grand Test covering only System of Particles and Rotational Motion under strict NEET exam conditions. Analyze every incorrect answer using this study guide.

Chapter Sub-Topics for Revision

1Center of Mass and Motion of Center of Mass
2Torque, Angular Momentum and Conservation Law
3Moment of Inertia, Radius of Gyration & Rolling Motion
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System of Particles and Rotational Motion is a high-yield chapter in NEET Physics, typically contributing 2 to 4 questions (approx. 8 to 16 marks) every year, making it crucial for a top rank.

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