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Physics (Class 11)November 13, 2026
Physics (Class 11)2-4 Questions (8-16 Marks)15 Free Practice MCQs

Motion in a Straight Line NEET Syllabus & 15-MCQ Online Test

Complete NTA NEET 2027 chapter syllabus breakdown, 5-year question weightage analysis, and 15 free NCERT line-by-line MCQs with official +4 / -1 marking.

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Motion in a Straight Line 15-MCQ Test

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Question 1 of 15Kinematics using calculus

A particle moves along a straight line such that its displacement ss at any time tt is given by s=t3−6t2+3t+4s = t^3 - 6t^2 + 3t + 4. The velocity of the particle when its acceleration is zero is:

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Reviewed by NEETnova Academic Council. Updated for NEET 2027 Syllabus.

Official NTA Data Verified

Comprehensive Master Guide: Motion in a Straight Line for NEET UG

Section 1: Official NTA NEET Syllabus & Sub-Topic Checklist

Detailed Sub-Topic Checklist (NCERT Class 11 Physics, Chapter 3)

  • 3.1 Introduction: Mechanical properties of motion, scalar and vector quantities, reference frames, and coordinate systems.
  • 3.2 Position, Path Length, and Displacement: Distinction between scalar path length (distance) and vector displacement (Δx=x2−x1\Delta x = x_2 - x_1), directional dependence, and non-decreasing distance monotonic nature vs. fluctuating displacement.
  • 3.3 Average Velocity and Average Speed: Mathematical definitions, vˉ=x2−x1t2−t1=ΔxΔt\bar{v} = \frac{x_2 - x_1}{t_2 - t_1} = \frac{\Delta x}{\Delta t} vs. Average Speed=Total Path LengthTotal Time Interval\text{Average Speed} = \frac{\text{Total Path Length}}{\text{Total Time Interval}}. Conditions where magnitude of average velocity equals average speed.
  • 3.4 Instantaneous Velocity and Speed: Limit as Δt→0\Delta t \to 0, v(t)=dxdtv(t) = \frac{dx}{dt}, graphical interpretation as slope of the position-time (x−tx-t) tangent, instantaneous speed as magnitude of instantaneous velocity.
  • 3.5 Acceleration: Average acceleration aˉ=ΔvΔt\bar{a} = \frac{\Delta v}{\Delta t}, instantaneous acceleration a(t)=dvdt=d2xdt2a(t) = \frac{dv}{dt} = \frac{d^2x}{dt^2}, physical significance of the sign of acceleration (speeding up vs. slowing down).
  • 3.6 Kinematic Equations for Uniformly Accelerated Motion: Derivations and applications of v=v0+atv = v_0 + at, x=x0+v0t+12x = x_0 + v_0t + \frac{1}{2}at2,and, and v2 = v02 + 2a(x - x0),plusthedisplacementinthe, plus the displacement in the n^{\text{th}}second:second:dn = u + \frac{a}{2}$$(2n - 1).
  • 3.7 Frame of Reference & Relative Velocity: One-dimensional relative velocity formula vAB=vA−vBv_{AB} = v_A - v_B, analysis of moving trains, overtaking problems, rain-man physics, and river-boat components along a straight line.
  • 3.8 Free Fall Motion: Special case of uniform acceleration with a=−ga = -g (taking vertically upward as positive), equations of motion under gravity, time of flight, maximum height, and velocity of impact.

Syllabus Status Comparison Table

NTA NEET UG Syllabus Sub-TopicStatusNCERT Text ReferenceScope / Exclusionary Note
Frame of Reference, Path Length & DisplacementRetainedSections 3.1, 3.2Strict 1D coordinate system formulation.
Average & Instantaneous Velocity/SpeedRetainedSections 3.3, 3.4Calculus-based differentiation and integration required.
Graphical Analysis (x−tx-t, v−tv-t, a−ta-t)RetainedSections 3.4, 3.5Slope and area calculations for linear and parabolic curves.
Kinematic Equations for Constant AccelerationRetainedSection 3.6Includes calculus and algebraic derivations; nthn^{\text{th}} second formula included.
Relative Velocity in 1DRetainedSection 3.7Relative motion problems restricted to straight line (trains, cars, rain-man).
Motion in a Plane (Projectiles, Vectors)MovedChapter 4Transferred entirely to "Motion in a Plane" chapter.
Relative Velocity in 2D (Boat-River, Rain-Wind)MovedChapter 4Removed from Chapter 3; vector components handled in Chapter 4.

Section 2: Previous 5-Year NEET Question Distribution (2022-2026) & Marks Weightage

Sub-Topic Question Distribution (NEET 2024–2026)

Sub-TopicNEET 2022NEET 2023NEET 2024NEET 2025NEET 2026Total QuestionsEstimated Weightage (%)
Position, Displacement & Average Speed/Velocity10110315%
Calculus-based Kinematics (x−tx-t, v−tv-t derivatives/integrals)11101420%
Kinematic Equations & nthn^{\text{th}} Second Formulas11011420%
Free Fall & Motion Under Gravity01111420%
Relative Velocity (1D / Trains / Overtaking)10111420%
Total Questions per Year4344419100%

NEETnova Strategic Insight

Motion in a Straight Line is a foundational mechanics chapter yielding 1 to 2 questions directly (worth 4 to 8 marks), while setting up concepts essential for Laws of Motion, Work, Energy, and Power.

  • Question Styles: Expect 1 numerical problem requiring calculus integration (e.g., given a(t)=3t+2a(t) = 3t + 2, find velocity or displacement), 1 graph-reading or area-under-curve problem (v−tv-t graph to displacement), 1 relative velocity word problem (such as two trains crossing or a car overtaking), and 1 standard free-fall or nthn^{\text{th}}-second kinematics application.
  • Assertion-Reasoning Trend: Frequently tests the sign conventions of acceleration and velocity. For instance: "Assertion: If the velocity of a particle is zero, its acceleration must be zero at that instant. Reason: Acceleration is the rate of change of velocity." (Students must identify that the assertion is false while the reason is a true statement, as a ball thrown vertically upward has zero velocity at its highest point, yet its acceleration is gg downward).

Section 3: High-Yield NCERT Line-by-Line Core Concepts & Exceptions

1. Mathematical Definitions and Calculus Relations

  • Displacement vs. Distance: Displacement Δx=xf−xi\Delta x = x_f - x_i can be positive, negative, or zero. Total path length (distance) is strictly non-decreasing: Δs=∫∣v∣dt\Delta s = \int |v| dt.
  • Average Speed vs. Magnitude of Average Velocity: \text{Average Speed} = $\frac{\text{Total Distance}}{\Delta t}$ $\ge$ $\le$ft|$\frac{\text{Total Displacement}}{\Delta$$ t}$\right| = |\text{Average Velocity}|
  • Differential Operations:
  • Position to Velocity: v(t)=dxdtv(t) = \frac{dx}{dt} (Slope of x−tx-t graph)
  • Velocity to Acceleration: a(t)=dvdt=d2xdt2a(t) = \frac{dv}{dt} = \frac{d^2x}{dt^2} (Slope of v−tv-t graph)
  • Acceleration to Velocity: v(t)=v0+∫t0ta(t) dtv(t) = v_0 + \int_{t_0}^{t} a(t) \, dt (Area under a−ta-t graph)
  • Velocity to Position: x(t)=x0+∫t0tv(t) dtx(t) = x_0 + \int_{t_0}^{t} v(t) \, dt (Area under v−tv-t graph)

2. Kinematic Equations for Uniformly Accelerated Motion (a=constanta = \text{constant})

When aa is constant, the standard equations apply:

  1. v=v0+atv = v_0 + at 2.2. x = x_0 + v_0t + \frac{1}{2}$$$at^{2}
  2. v2=v02+2a(x−x0)v^2 = v_0^2 + 2a(x - x_0)
  3. Displacement in the exact nthn^{\text{th}} second: $$d_n = x(n) - x(n-1) = v_0 + \frac{a}{2}$(2n - 1)$$$$

3. Special Case: Free Fall Motion Under Gravity

  • Choosing the upward direction as positive (+y+y):
  • Acceleration a=−ga = -g (where g≈9.8 m/s2g \approx 9.8 \text{ m/s}^2 or 10 m/s210 \text{ m/s}^2 as specified in the test item).
  • Time to reach maximum height (v=0v = 0): tup=v0gt_{\text{up}} = \frac{v_0}{g}
  • Maximum height attained from launch point: Hmax⁡=v022gH_{\max} = \frac{v_0^2}{2g}
  • Total time of flight for a projectile dropped back to launch elevation: T=2v0gT = \frac{2v_0}{g}
  • Symmetry Property: The magnitude of velocity with which a body is thrown upward is equal to the magnitude of velocity with which it strikes the ground upon return (∣vfinal∣=∣vinitial∣|v_{\text{final}}| = |v_{\text{initial}}|). The time taken to ascend equals the time taken to descend.

4. Relative Velocity in One Dimension

  • Velocity of object A relative to object B: vAB=vA−vBv_{AB} = v_A - v_B
  • If two trains of lengths L1L_1 and L2L_2 move in opposite directions with velocities v1v_1 and v2v_2:
  • Relative speed of approach = v1+v2v_1 + v_2
  • Total time to completely cross each other: t=L1+L2v1+v2t = \frac{L_1 + L_2}{v_1 + v_2}
  • If moving in the same direction:
  • Relative speed = $|v_{1} - v_{2}|
  • Time to overtake: t=L1+L2∣v1−v2∣t = \frac{L_1 + L_2}{|v_1 - v_2|}

5. NCERT Textual Exceptions & Graphical Highlights

  • Non-Uniform Acceleration: If aa is variable (e.g., a=kta = kt), standard kinematic equations v2=v02+2asv^2 = v_0^2 + 2as cannot be used. You must resort strictly to calculus definitions: a=vdvdxa = v \frac{dv}{dx} and v=dxdtv = \frac{dx}{dt}.
  • x−tx-t Graph Inflection Points: An inflection point on an x−tx-t graph (where concavity changes from concave up to concave down, or vice versa) represents a point where acceleration a(t)=d2xdt2a(t) = \frac{d^2x}{dt^2} passes through zero.
  • Total Distance Trap with Turning Points: If a particle's velocity changes sign (turns around), total distance calculated via ∫v dt\int v \, dt will yield zero net displacement if it returns to the start. To get distance, you must integrate the absolute value of velocity: ∫∣v∣ dt\int |v| \, dt.

Section 4: Negative Marking Pitfalls & Calculation/Conceptual Traps

  1. Confusing Average Speed with the Magnitude of Average Velocity:
  • Trap: A particle moves in a semicircle of radius RR from point A to point B in time TT. Students often calculate average velocity magnitude as DistanceT=πRT\frac{\text{Distance}}{T} = \frac{\pi R}{T}, matching the average speed formula.
  • Correction: Average speed is πRT\frac{\pi R}{T}, but magnitude of average velocity is DisplacementT=2RT\frac{\text{Displacement}}{T} = \frac{2R}{T}.
  1. Incorrect Sign Conventions in Free Fall:
  • Trap: Dropping a sign on acceleration due to gravity (gg) when substituting into v2=u2+2ghv^2 = u^2 + 2gh. If taking downward as negative, both displacement and acceleration are negative, making v2=0+2(−g)(−h)=2ghv^2 = 0 + 2(-g)(-h) = 2gh. Forgetting both negative signs leads to correct numerical magnitudes by coincidence, but substituting only one results in a
  1. Misinterpreting the "nthn^{\text{th}} Second" Formula:
  • Trap: Calculating distance traveled during the 4th4^{\text{th}} second by evaluating x(t)x(t) at t=4t = 4 seconds.
  • Correction: x(4)x(4) is the total distance from t=0t = 0 to t=4t = 4. The distance during the 4th4^{\text{th}} second is the interval from t=3t = 3 to t=4t = 4, given explicitly by d4=u+a2d_4 = u + \frac{a}{2}(2(4) - 1) = u + $\frac{7a}{2}$$.
  1. Area Under v−tv-t Graph vs. Slope of v−tv-t Graph:
  • Trap: Under exam pressure, students mix up the operations: taking the slope of a v−tv-t graph when asked for displacement (which yields acceleration), or integrating/finding the area under an x−tx-t graph (which has no direct physical meaning unless multiplied by time axis).
  • Correction:
  • x−tx-t slope = Velocity (vv)
  • v−tv-t slope = Acceleration (aa)
  • v−tv-t area = Displacement (Δx\Delta x)
  • a−ta-t area = Change in Velocity (Δv\Delta v)
  1. Relative Velocity Direction Blunders:
  • Trap: Writing vAB=vA+vBv_{AB} = v_A + v_B when two bodies move in the same direction.
  • Correction: Vector subtraction applies: vAB=vA−vBv_{AB} = v_A - v_B. If car A moves at 60 km/h60 \text{ km/h} East and car B moves at 40 km/h40 \text{ km/h} East, velocity of A relative to B is 60−40=+20 km/h60 - 40 = +20 \text{ km/h} (meaning B sees A moving forward at 20 km/h20 \text{ km/h}).

Section 5: Step-by-Step 5-Day Mastery Strategy for NEET Aspirants

Day 1: Fundamentals of Motion, Distance, Displacement, and Speed

  • Core Focus: Master scalar vs. vector quantities, path length, and displacement through numerical visualization.
  • NCERT Reading: Read Chapter 3, Sections 3.1, 3.2, and 3.3 line by line.
  • Problem-Solving Focus: Solve 30 problems on average speed involving equal distances vs. equal time intervals (e.g., vavg=2v1v2v1+v2v_{\text{avg}} = \frac{2v_1v_2}{v_1 + v_2} vs. vavg=v1+v22v_{\text{avg}} = \frac{v_1 + v_2}{2}).
  • Active Revision: Write down dimensional formulas and units for all kinematic quantities.

Day 2: Calculus-Based Kinematics & Graphical Analysis

  • Core Focus: Master differentiation (x→v→ax \to v \to a) and integration (a→v→xa \to v \to x), along with slope and area interpretations of x−tx-t, v−tv-t, and a−ta-t graphs.
  • NCERT Reading: Read Sections 3.4 and 3.5. Review all graph figures in NCERT.
  • Problem-Solving Focus: Solve 35 problems involving variable acceleration where integration is required to find velocity and position functions. Solve at least 15 graph-reading numericals (calculating total distance vs. displacement from a v−tv-t curve).
  • Active Revision: Practice deriving kinematic equations via calculus integration (dv=a dtdv = a \, dt and dx=v dtdx = v \, dt).

Day 3: Kinematic Equations for Uniform Acceleration & The nthn^{\text{th}} Second

  • Core Focus: Apply the three primary equations of motion and the nthn^{\text{th}} second displacement formula without algebraic errors.
  • NCERT Reading: Read Section 3.6 thoroughly. Pay attention to solved examples 3.3, 3.4, and 3.5.
  • Problem-Solving Focus: Solve 40 questions focusing on braking distance, stopping time, acceleration/deceleration combinations, and bullet-penetration problems (v2=u2+2asv^2 = u^2 + 2as).
  • Active Revision: Memorize the ratio of distances covered in successive equal time intervals for bodies starting from rest (1:3:5:7…1 : 3 : 5 : 7 \dots).

Day 4: Free Fall Motion and Motion Under Gravity

  • Core Focus: Master sign conventions for vertically projected bodies, maximum height calculations, time of flight, and symmetry properties.
  • NCERT Reading: Read Section 3.6 (gravity subsections) and NCERT Example 3.6 and 3.7.
  • Problem-Solving Focus: Solve 35 problems on balls dropped from towers, stones thrown upward, objects crossing each other in mid-air, and multi-stage drop problems (e.g., a balloon rising while dropping a stone).
  • Active Revision: Create short notes on shortcut formulas for free-fall (Hmax⁡=u22gH_{\max} = \frac{u^2}{2g}, T=2ugT = \frac{2u}{g}).

Day 5: Relative Velocity in 1D, Mixed-Concept Practice & Mock Drill

  • Core Focus: Master 1D relative velocity (trains, cars, overtaking) and complete a timed NEET-style chapter test.
  • NCERT Reading: Read Section 3.7. Review summary points at the end of the chapter.
  • Problem-Solving Focus: Solve 25 problems on relative velocity. Then, take a strict 45-minute timed mock test containing 25 high-yield multiple-choice questions (including statement-based and assertion-reasoning questions) from Chapter 3.
  • Active Revision: Analyze all incorrect answers from the mock test, log calculation errors or conceptual gaps in an error notebook, and review formulas.

Chapter Sub-Topics for Revision

1Position-Time and Velocity-Time Graphs
2Kinematic Equations for Uniformly Accelerated Motion
3Relative Velocity and Free Fall Motion
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Frequently Asked Questions

Common queries and official guidelines verified by NEETnova Academic Council.

Motion in a Straight Line typically yields 2 to 4 questions in the NEET UG exam, translating to 8 to 16 marks. It forms the fundamental basis for Mechanics and is considered a high-yield core topic for Class 11 Physics.

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